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144=(-16t^2)+64t+80
We move all terms to the left:
144-((-16t^2)+64t+80)=0
We calculate terms in parentheses: -((-16t^2)+64t+80), so:We get rid of parentheses
(-16t^2)+64t+80
We get rid of parentheses
-16t^2+64t+80
Back to the equation:
-(-16t^2+64t+80)
16t^2-64t-80+144=0
We add all the numbers together, and all the variables
16t^2-64t+64=0
a = 16; b = -64; c = +64;
Δ = b2-4ac
Δ = -642-4·16·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{64}{32}=2$
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